11) Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricke
- 1) 75
- 2) 100
- 3) 125
- 4) 150
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Ans. B
Explanation :
Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
\begin{aligned}
= n(A\cup B) = 450-50 = 400\\text{Required Number}, n(A \cap B) \= n(A)+n(B)-n(A\cup B) \= 325 + 175 - 400 = 100
\end{aligned}
12) In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch
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Ans. D
Explanation :
\begin{aligned}
n(A) = \left(\frac{60}{100}*96\right) = \frac{288}{5} \n(B) = \left(\frac{30}{100}*96\right) = \frac{144}{5} \n(A\cap B) = \left(\frac{15}{100}*96\right) = \frac{72}{5} \\text{People who have either or both lunch} \n(A\cup B) = \frac{288}{5}+\frac{144}{5}-\frac{72}{5} \= \frac{360}{5} = 72
\end{aligned}
So People who do no have either lunch were = 96 -72
= 24
13) How many litres of pure acid are there in 8 litres of a 20% solut
- 1) 1.5
- 2) 1.6
- 3) 1.7
- 4) 1.8
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Ans. B
Explanation :
Question of this type looks a bit typical, but it is too simple, as below...
It will be 8 * 20/100 = 1.6
14) A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transact
- 1) 9%
- 2) 10%
- 3) 11%
- 4) 12%
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Ans. A
Explanation :
Actual Price = Rs.25 + Rs.2.50 = Rs.27.5
Saving = Rs.2.5
\begin{aligned}\text{Percentage Saving = }\dfrac{2.5}{27.5}\times 100 \\
= \dfrac{250}{27.5} = \dfrac{2500}{275}\\
= \dfrac{100}{11} = 9\dfrac{1}{11}\% \approx 9\%\end{aligned}
15) If number x is 10% less than another number y and y is 10% more than 125, then find out the value o
- 1) 123.55
- 2) 123.65
- 3) 123.75
- 4) 123.85
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16) Raman's salary was decreased by 50% and subsequently increased by 50%. How much percent does he lo
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Ans. D
Explanation :
Let the origianl salary = Rs. 100
It will be 150% of (50% of 100)
= (150/100) * (50/100) * 100 = 75
So New salary is 75, It means his loss is 25%
17) A student multiplied a number by 3/5 instead of 5/3. What is the percentage err
- 1) 64%
- 2) 65%
- 3) 66%
- 4) 67%
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Ans. A
Explanation :
Let the number be x,
then,
\begin{aligned}
\frac{5}{3} - \frac{3}{5} = \frac{16}{15}x
\end{aligned}
Error% = \begin{aligned}
(\frac{16}{15}x * \frac{3}{5} * 100)% = 64%
\end{aligned}
18) If x% of y is 100 and y% of z is 200, then find the relation between x and
- 1) z = x
- 2) 2z = x
- 3) z = 2x
- 4) None of above
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Ans. C
Explanation :
It is , y% of z = 2(x% of y)
=> yz/100 = 2xy/100
=> z = 2x
19) Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys
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Ans. B
Explanation :
Clearly,
x% of 150 = 150 - x [as x is number of boys]
\begin{aligned}
=> x + \frac{x}{100} * 150 = 150 \
=> \frac{5}{2}x = 150 \
=> x = 60 \\end{aligned}
20) 2 is what percent of
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Ans. B
Explanation :
2/50 * 100 = 1/25 * 100 = 4 %