1) What is the difference between the number of Literate Males and Literate Females, If total number is 2,50,000
- 1) 3500
- 2) 4500
- 3) 5000
- 4) 6000
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Ans. C
Explanation :
Difference = (35%of 250000)-(33% of 250000)
= (35% - 33%) of 250000
= 2% of 250000
= 2/100 * 250000
= 5000
2) What is the central angle of the sector corresponding to the expenditure incurred on Royalty
- 1) 54 degree
- 2) 48 degree
- 3) 45 degree
- 4) 40 degree
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Ans. A
Explanation :
Central angle corresponding to the royalty will be,
15% of 360 degree
= 15/100*360
= 3*18 = 54 degree
3) Which two expenditures together have a central angle of 108 degree in pie chart
- 1) Binding cost + Royalty cost
- 2) Printing cost + Paper cost
- 3) Binding cost + Transportation cost
- 4) Printing cost + Transportation cost
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Ans. D
Explanation :
This type of question can be solved, first by getting 108 degree is what percent of 360, Then choosing the correct option.
So let solve,
108 is what percent of 360 ?
\begin{aligned}
= \frac{108}{360}*100 \% \= 30\% \text{ of expenditure} \\end{aligned}
So from the options given, it is clear that
Printing cost(20%) + Transportation cost(10%)
= 30%
4) If the difference between the two expenditures are represented by 18 degree in the pie chart, then which option of following can be correct
- 1) Binding cost and Royalty cost
- 2) Paper cost and Printing cost
- 3) Paper cost and Royalty
- 4) Royalty and Promotion cost
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Ans. B
Explanation :
18 is what percent of 360 ?
\begin{aligned}
\frac{18}{360}*100 \% \= 5 \%
\end{aligned}
So Paper cost and Printing cost is the answer because
(25% - 20%) = 5 %
5) If for a edition of a book, the cost of paper is Rs. 56250, then find the promotion cost for this edition
- 1) Rs 21500
- 2) Rs 22300
- 3) Rs 22500
- 4) Rs 22700
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Ans. C
Explanation :
We are having the ratios of the percentage of two (from pie chart) also having cost of one.
So we can solve it in a easy way as,
\begin{aligned}
25:10 = 56250:p \=> p = \left( \frac{56250*10}{25}\right) \= Rs.& 22500
\end{aligned}
6) If for the certain quantity of books, the publisher has to pay Rs 30,600 as printing cost, then what will be the amount of royalty to be paid for these books
- 1) Rs 22650
- 2) Rs 22750
- 3) Rs 22850
- 4) Rs 22950
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Ans. D
Explanation :
Let the royalty of to be paid for these books be Rs r.
then
\begin{aligned}
20:15 = 30600:r \=> r = \frac{30600*15}{20} \=> r = 22950
\end{aligned}
7) If 5500 copies are published and the transportation cost on them amounts to Rs. 82500, then what should be the selling price of the book so that the publisher can earn a profit of 25 %
- 1) Rs 180.50
- 2) Rs 182.50
- 3) Rs 183.50
- 4) Rs 187.50
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Ans. D
Explanation :
For the publisher to earn a profit of 25%, S.P. = 125% of C.P.
Also transportation Cost = 10% of C.P.
Let the S.P. of 5500 books be Rs x.
\begin{aligned}
10:125 = 82500:x \=> x = \frac{125*82500}{10} \=> x = 1031250 \\text{S.P. of one book =}\frac{1031250}{5500} \= 187.50
\end{aligned}
8) Royalty on the book is less than the printing cost by
- 1) 20%
- 2) 25%
- 3) 30%
- 4) 35%
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Ans. B
Explanation :
Printing cost of book = 20% of C.P.
Royalty on book = 15% of C.P.
Difference = (20%-15%) = 5% of C.P.
\begin{aligned}
\text{Percentage Differene =}\\left( \frac{Difference}{\text{Printing Cost}} *100 \right)\% \= \left( \frac{\text{5% of C.P.}}{\text{20% of C.P.}}*100 \right)\% \= 25\%
\end{aligned}
9) If company could receive a total of Rs. 9695 crores as External Assistance, by what percent (approximately) should it increase the Market Borrowing to arrange for the shortage of fund
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Ans. B
Explanation :
New funds = 11486 - 9695
= Rs. 1791 crores
Increase in requirement of market borrowing is 1791 crore
Now, 1791 crore is what percent of Market Borrowing
\begin{aligned}
= \frac{1791}{29952}*100\% \= 5.98 \%
= 6\%\text{ (approx)}
\end{aligned}
10) The central angle corresponding to Market Borrowing is
- 1) 187.2 degree
- 2) 183.2 degree
- 3) 181.2 degree
- 4) 180.2 degree
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Ans. A
Explanation :
Central angle corresponding to Market Borrowing
\begin{aligned}
\left(\frac{29952}{57600}*360\right) \= 187.2 \text{ degree}
\end{aligned}