11) Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years he
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Ans. D
Explanation :
Sachin's age today = 30 years.
Sachin's age 10 years back = 20 years.
Ajay's age 10 years back = 10 years.
Ajay's age today =20 years
12) In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B
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Ans. C
Explanation :
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(xâ€”10)
hence x=39.
Present age of B = 39 years
13) Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present a
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Ans. B
Explanation :
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
14) Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal to
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Ans. A
Explanation :
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
15) Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at pres
- 1) 10 years
- 2) 12 years
- 3) 14 years
- 4) 16 years
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Ans. D
Explanation :
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
\begin{aligned}
=> \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
\end{aligned}
\begin{aligned}
<=> 10(6x+10) = 11(5x+10)
\end{aligned}
\begin{aligned}
<=> 5x = 10 => x = 2
\end{aligned}
So Sagar age is (5x+6) = 16
16) Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D
- 1) 90
- 2) 98
- 3) 120
- 4) Data is not adequate
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17) Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at pres
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Ans. B
Explanation :
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
Bâ€™s present age = (2x + 10) =30 years
18) A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son
- 1) 20 years
- 2) 21 years
- 3) 22 years
- 4) 24 years
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Ans. C
Explanation :
Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
19) Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ag
- 1) 16,35,36
- 2) 12,28,36
- 3) 16,28,27
- 4) 16,28,36
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Ans. D
Explanation :
Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4
So their present ages are: 16,28,36
20) A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son
- 1) 21 years
- 2) 22 years
- 3) 23 years
- 4) 24 years
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Ans. B
Explanation :
Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years